Sex Linked Genes

 

Punnett Square
Monohybrid Problems
Dihybrid Problems
Mendelian Variations
Crossingover
Sex Linked Genes


Sex Determination: Inheritance of Sex-Linked Traits


In higher plant and animals, the cells which make up the body cells of the adult are usually diploid and referred to as somatic cells. The gametes which are produced in the sex organs are always haploid.

Fill in the following chart and place in your notes.

Terms Description of terms
Somatic Cells  
Gametes  
Diploid  
Haploid  



Read the pages in you text describing sex determination and sex linkage. Study behavioral objectives 14, 15 and 16. Sex determination in mammals and some insects, is determined by the presence of a special pair of chromosomes called sex chromosomes. In males there are 22 homologous chromosome pairs and two essentially unpaired chromosomes of different sizes carrying different genes. These unpaired chromosomes (sex chromosomes) may be indicated by XY. The human male cell contains 44 regular chromosomes (autosomes) and two sex chromosomes. The human female cell contains 23 homologous chromosome pairs. The female cells contain 44 autosomes and two sex chromosomes. These pair of chromosomes are usually  indicated by XX. The early embryological differentiation of males and females is apparently based on the presence or absence of the Y chromosome. The presence of the Y chromosome results in the production of the combination of phenotypic characteristics of the male. Absence of the Y chromosome results in the physical development of a phenotypic female. For the most part the genes on the Y chromosome are nonfunctional. The Y carries relative few genes other than those determining maleness. Example: The gene which produces testosterone is located on the Y chromosome. Read the pages concerning sex linked traits and character and study behavioral objectives 14, 15 and 16.


An individual with a XX chromosome will develop into a female and an individual with a XY chromosome pair will develop into a male.



1. How many autosomes are present in a human male's somatic cell?


Answer as follows:

The human male's somatic cell contains 44 autosomes and two sex chromosomes.



2. How many autosomes are present in a human male's gamete (sperm)?

Answer as follows:

The human male's gamete contains 22 autosomes and two unpaired chromosomes.



3. Which of the following chromosome combinations would be found in a female's somatic cell?

a) 22 autosomes and 1 X chromosome 
b) 44 autosomes, 1 X and 1 Y chromosome
c) 46 autosomes
d) 44 autosomes and 2 X chromosomes                                                           e) 22 autosomes and 2 X chromosomes

Answer as follows:

The correct answer is "d".




4. Which of the following chromosome combinations would be found in a male's diploid somatic cell?

a) 22 autosomes and 1 X chromosome
b) 44 autosomes, 1 X and 1 Y chromosome 
c) 46 autosomes
d) 44 autosomes and 2 X chromosomes                                                           e) 22 autosomes and 2 X chromosomes


Answer as follows:


The correct answer is "b".



5. Which of the following chromosome combinations would be found in a female's gamete (egg)?

a) 22 autosomes and 1 X chromosome 
b) 44 autosomes, 1 X and 1 Y chromosome 
c) 46 autosomes
d) 44 autosomes and 2 X chromosomes
e) 22 autosomes and 2 X chromosomes

Answer as follows:

The correct answer is "a".

6. Which of the following chromosome combinations would be found in a male's  haploid cell (sperm)?

a) 22 autosomes and 1 X chromosome
b) 44 autosomes, 1 X and 1 Y chromosome 
c) 46 autosomes
d) 44 autosomes and 2 X chromosomes                                                            e) 22 autosomes and 2 X chromosomes


Answer as follows:

The correct answer is b.


During meiosis in females since the somatic cells all contain XX chromosomes, the gametes (eggs) will all contain a single X chromosome. During meiosis in males since the somatic cells all contain XY chromosomes, the gametes (sperm) will contain a single X chromosome and a single Y chromosome.

7. Work the problem showing the segregating of the X and Y chromosomes in humans.

XX    x     XY

Answer as follows:

////////////      X     Y
   X    XX    XY
   X    XX    XY





8. Who determines the sex of the child?

Answer as follows:

The Y chromosome contributes to determination of  the sex of the child.


Remember these are entire chromosomes and not genes that controls the sex of an individual. These chromosomes contain genes which may be passed on to their offspring. These type of problems are called sex-linked problems. Sex linked problems are worked like the monohybrid problems you worked earlier. Keep in mind that when you work six-linked problems the Y chromosome is nonfunctional.

Example: Red/green color blindness is a sex linked trait. Individual who are not red/green color blind (normal) contain a dominant allele (N) for this trait. Individuals who are red/green color blind are homozygous recessive for this trait. Since these genes are located on the X and Y chromosome the genotypes may be written as follows. Note: Alleles are not placed on the Y chromosome because they are nonfunctional. The combination of X and Y determines the sex and the superscript allele represents the gene associated with the sex chromosomes.

XNXN         is a female normal for red/green color blindness (not color blind).
XNXn          is a female normal for red/green color blindness (not color blind);
                    however, she is a carrier for this allele.
XnX          is a female who is red/green color blinded.
XNY            is a male normal for red/green color blindness (not color blind).
XnY             is a male who is red/color blinded.

9. Can males be heterozygous for sex linked traits?

Answer as follows:

No.  Only the "X"  chromosome is active, therefore; whatever allele is located on the "X" chromosome will be present.



10. In fruit flies (Drosophila) the gene for red or white eyes is located on the sex chromosome. Red (RR or Rr) is dominant to white (rr). State the possible genotypes of both parents when a red-eyed male Drosophila is crossed with a  red-eyed female and the resulting offspring include:

19 red-eyed males
11 red-eyed females
10 white-eyed males

Answer as follows:

XX = female,  XY = male

19 red eyed males  =    XRY   The XR had to come from the female parent.

11 red eyed females =  XRX-   Since all females have red eyes the male must have a                                     XR allele.

10 white eyed males =  XrY and    XRY  Since there are both red eye and white                                     eye males the mother must be heterozygous.
 

               Parents are:     XRXr   x    XRY   


11. In fruit flies (Drosophila) the gene for red or white eyes is located on the sex chromosome. Red (RR or Rr) is dominant to white (rr). State the possible genotypes of both parents when the following F1 offspring were observed:

10 red-eyed males
9 red-eyed females
9 white-eyed males
8 white-eyed females

Answer as follows:

    
     XRXr   x      XrY



12. Normal vision (C) is dominant over color blind (c). This gene is located on the sex chromosome. A normal vision man and woman produce three boys, one of which is color blind and the other two with normal vision. What are the genotypes of the parents.

Answer as follows:

   

     XCXc   x      XCY

Work Punnett square to check.

13. The disease hemophilia is caused by a recessive allele carried on the X chromosome. What are the possible genotypes of a father when all his sons are hemophiliacs?

Answer as follows:

Can not be determined. Only the mother passes sex-linked to the boys.

         


14. Consider the following parents:   XHXh   x      XhY

What percent of the male's sperm contain the Xh allele?

Answer as follows:


50% will contain the chromosome with the Xh alleles and 50% will contain the Y chromosome.


15. Consider the following parents:    XHX  x     XhY

What percent of the female's eggs contain the dominant allele?

Answer as follows:

\\\\\\\\\\\\\\\\\\\\\\\ XH Xh
Xh XHXh XhXh
Y XHY XhY

50% of the females eggs will contain XH alleles.


16. Consider the following parents:    XHXh  x   XhY


What are the chances for these two parents to have a boy with hemophilia?a girl with hemophilia?

Answer as follows:

\\\\\\\\\\\\\\\\\\\\\\\ XH Xh
Xh XHXh XhXh
Y XHY XhY

The changes of having a boy with hemophilia is 25% and to having a girl with hemophilia is 25%.


This is the end of the lesson involving sex linkage. In the next lesson you will learn that many genes may be located on the same chromosome. You work the problems the same way as demonstrated in the lesson involving monohybrid crosses, however two or more genes will segregate out on the same chromosome.  Go back to the home page and go to the lesson,  Linked Genes and Crossing-over.



 

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Last modified: August 12, 2005